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The equilibrium constant for the reversi...

The equilibrium constant for the reversible reaction `N_(2)+3H_(2) hArr 2NH_(3)` is K and for the reaction `(1)/(2) N_(2)+(3)/(2) H_(2) hArr NH_(3)` , the equilibrium constant is `K',.K` and `K'` will be related as

A

`K=K`

B

`K = sqrt(k)`

C

`K=sqrt(K)`

D

`Kxx K=1`

Text Solution

Verified by Experts

The correct Answer is:
B
`K=sqrt(K)`
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