Formula of cane sugar is `C_(12)H_(22)O_(11)`. No. of molecules present in 34.2 g of cane sugar is

Options

A. `6.022 xx 10^(21)`
B. `6.022 xx 10^(20)`
C. `6.022 xx 10^(22)`
D. `6.022 xx 10^(18)`

Answer

C

Explanation

Gram molecular mass of cane sugar `(C_(12)H_(22)O_(11))`
`= 12xx12 +22 xx 1 +16 xx11`
`= 342.0 g`
342.0 g of can sugar contain
`=6.022 xx 10^(23)` molecules
34.2 g of cane sugar contain
`= (34.2)/(342)xx6.022xx10^(23)`
`=6.022 x 10^(22)` molecules.