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If 0.5 mole of BaCl(2) is mixed with 0.2...

If 0.5 mole of `BaCl_(2)` is mixed with 0.20 mole of `Na_(3)PO_(4)`, the maximum number of `Ba_(3)(PO_(4))_(2)` that can be formed is :

A

`0.70`

B

`0.50`

C

`0.20`

D

`0.10`

Text Solution

Verified by Experts

The correct Answer is:
D
`underset("0.5 mol")(3BaCl_(2))+underset("0.2 mol")(2Na_(3))PO_(4)rarrBa_(3)(PO_(4))_(2)+6NaCl`
`Na_(3)PO_(4)` is the limiting reactant
`:.` No. of moles of `Ba_(3)(PO_(4))_(2)=0.1` mol
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Knowledge Check

  • If 0.5 mole of BaCl_(2) is mixed with 0.2 mole of Na_(3)PO_(4) the maximum number of mole of Ba_(3)(PO_(4))_(2) that can be formed is

    A
    `0.7`
    B
    `0.5`
    C
    `0.30`
    D
    `0.1`

  • If 0.5 mol of BaCl_(2) is mixed with 0.2 mole of Na_(3)PO_(4) , the maximum number of moles of Ba_(3)(PO_(4))_(2) that can be formed is

    A
    0.7
    B
    0.5
    C
    0.3
    D
    0.1

  • If 0.5 mol of BaCl_(2) is mixed with 0.2 mol of Na_(3)PO_(4) , the maximum number of moles of Ba_(3)(PO_(4))_(2) that can be formed is

    A
    `0.7`
    B
    `0.5`
    C
    `0.1`
    D
    `0.2`

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