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No. of H(2)O molecules in a drop of wate...

No. of `H_(2)O` molecules in a drop of water weighing 0.05 g is :

A

`1.15 xx 10^(23)`

B

`1.672 xx 10^(21)`

C

`1.5 xx 10^(20)`

D

`6.022 xx 10^(22)`

Text Solution

Verified by Experts

The correct Answer is:
B
18.0 g of `H_(2)O` contain molecules
`=6.022 xx 10^(23)`
0.05 g of `H_(2)O` contain molecules
`= ((0.05g))/((18.0g))xx6.022xx10^(23)`
`=1.673xx10^(21)` molecules.
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Knowledge Check

  • The number of H_(2)O molecules in a drop of water weighing 0.018 g is :

    A
    `6.022 xx 10^(26)`
    B
    `6.022 xx 10^(23)`
    C
    `6.022 xx 10^(19)`
    D
    `6.022 xx 10^(20)`

  • The number of water molecules present in a drop of water weighing 0.018 g is

    A
    `6.022 xx 10^(26)`
    B
    `6.022 xx 10^(23)`
    C
    `6.022 xx 10^(19)`
    D
    `6.022 xx 10^(20)`

  • The number of water molecules present in a drop of water weighing 0.018 g is

    A
    `6.022xx10^(26)`
    B
    `6.022xx10^(23)`
    C
    `6.022xx10^(20)`
    D
    `6.022xx10^(19)`

    • Similar Questions

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    What is the number of water molecules contained in a drop of water weighing 0.06 g ?

    The volume of a drop of water is 0.04 mL . How many H_(2) O molecules are there in a drop of a water? d = 1.0 g mL .

    If 1 mL of water contain 20 drops. Then no. of molecules in a drop of water is

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