Bond angle in `H_(2)S` is lower than in `H_(2)O`. Justify.

Explanation

Bond angle in `H_(2)O
(104.5^(@))` is higher than the bond angle in `H_(2)S (92^(@))`. The difference in the bond angles is linked with the electronegativities of the oxygen and sulphur atoms. As the electronegativity of the central atom decreases, bond angle decreases. In the present case, S is less electronegative than oxygen. Now, since oxygen is more electronegative than sulphur therefore, the electron density around oxygen in `H_(2)O` is more than around sulphur in `H_(2)S`. As a result, the bond angle in `H_(2)O` is more than the bond angle in `H_(2)S` .