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How many grams of CaO are required to ne...

How many grams of CaO are required to neutralise 852 g of `P_(4)O_(10)` ? Draw structure of `P_(4)O_(10)` molecule.

Text Solution

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`underset(=336g)underset(6xx56)(6CaO) " " + " " underset(=284g)underset(4xx31+16xx10)(P_(4)O_(10)) " " to 2Ca_(3)(PO_(4))_(2)`
284 g of `P_(4)O_(10)` need CaO=336 g
852 g of `P_(4)O_(10)` need `CaO=((336g)xx(852g))/((284))=1008 g`
For structure of `P_(4)O_(10)`, consult Fig. 3 (Section 4)
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How many grams of CaO are required to neutralise 852g of P_(4)O_(10) ?

How many grams of CaO are required to neutralise 852 g of P_4 O_10 ? Draw the structure of P_4 O_10 .

Knowledge Check

  • In P_(4)O_(10) ,

    A
    second bond in P=O is formed by `ppi-dpi` back bonding
    B
    P=O bond is formed by `ppi-ppi` bonding
    C
    P=O bond is formed by `dpi-dpi` bonding
    D
    P=O bond is formed by `dpi-dpi-3 sigma` back bonding
  • P_(4)O_(10) is an anhydride of :

    A
    `H_(3)PO_(2)`
    B
    `H_(3)PO_(3)`
    C
    `H_(3)PO_(4)`
    D
    `H_(4)P_(2)O_(7)`
  • P_(4) O_(10) is an anhydride of-

    A
    `H_(2)P_(2)O_(7)`
    B
    `H_(3)PO_(4)`
    C
    `HPO_(3)`
    D
    `H_(3)PO_(3)`
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    Draw the structure of P_(4)O_(10) .

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    How many molecules of water are required to obtain orthophoshoric acid from 1 mole P_(4)O_(10) ?

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