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The momentum of a body is p and its kine...

The momentum of a body is p and its kinetic energy is E. Its momentum becomes 2p. Its kinetic energy will be

A

`(E )/(2)`

B

3E

C

2E

D

4E

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to understand the relationship between momentum and kinetic energy. Let's break it down step by step. ### Step 1: Understand the given quantities - Initial momentum \( p \) - Initial kinetic energy \( E \) - Final momentum \( 2p \) ### Step 2: Recall the relationship between momentum and kinetic energy The relationship between momentum \( p \) and kinetic energy \( E \) is given by the formula: \[ E = \frac{p^2}{2m} \] where \( m \) is the mass of the body. ### Step 3: Calculate the initial kinetic energy Using the formula, we can express the initial kinetic energy in terms of momentum: \[ E = \frac{p^2}{2m} \] ### Step 4: Calculate the final kinetic energy when momentum is \( 2p \) Now, we need to find the final kinetic energy when the momentum becomes \( 2p \). We can substitute \( 2p \) into the kinetic energy formula: \[ E' = \frac{(2p)^2}{2m} \] ### Step 5: Simplify the expression for final kinetic energy Calculating \( (2p)^2 \): \[ E' = \frac{4p^2}{2m} \] This simplifies to: \[ E' = 2 \cdot \frac{p^2}{2m} = 2E \] ### Step 6: Conclusion Thus, the final kinetic energy \( E' \) when the momentum is \( 2p \) is: \[ E' = 2E \] ### Final Answer The final kinetic energy will be \( 2E \). ---

To solve the problem, we need to understand the relationship between momentum and kinetic energy. Let's break it down step by step. ### Step 1: Understand the given quantities - Initial momentum \( p \) - Initial kinetic energy \( E \) - Final momentum \( 2p \) ### Step 2: Recall the relationship between momentum and kinetic energy ...
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Knowledge Check

  • If the momentum of a body is doubled, the kinetic energy is _____.

    A
    becomes 1/4 times
    B
    Unchanged
    C
    Doubled
    D
    becomes 4 times
  • When the momentum of a body a doubled, the kinetic energy is

    A
    doubled
    B
    halved
    C
    becomes four times
    D
    becomes three times
  • A particle of mass m has momentum p. Its kinetic energy will be

    A
    mp
    B
    `p^(2)m`
    C
    `(p^(2)/(m)`
    D
    `p^(2)/(2m)`
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