The figure shows the variation of potential energy of a particle as a funcation pf x, the x-coordination of the region. It has been assumed that potential energy depends only on `x`. For all other values `x, U` is zero. i.e. for` x lt - 10` and `x gt 15, U = 0`. If total mechanical energy of the particle is `25J`, then it can found in the region
A
`-10ltxlt-5` and `6ltxlt15`
B
`-10ltxlt0` and `6 ltxlt10`
C
`-5ltxlt6`
D
`-10ltxlt10`
Text Solution
Verified by Experts
The correct Answer is:
A
`U=E-K=25-K` Since, `Kge0` `:. U le 25J`
Topper's Solved these Questions
WORK, ENERGY & POWER
DC PANDEY|Exercise Level 2 Subjective|15 Videos
WAVE MOTION
DC PANDEY|Exercise Integer Type Question|11 Videos
WORK, ENERGY AND POWER
DC PANDEY|Exercise MEDICAL ENTRACES GALLERY|33 Videos
Similar Questions
Explore conceptually related problems
The figure shows the variation of potential energy of a particle as a funcation pf x, the x-coordination of the region. It has been assumed that potential energy depends only on x . For all other values x, U is zero. i.e. for x lt - 10 and x gt 15, U = 0 . If total mechanical energy of the particle is -40J , then it can be found in region.
Figure shows the variation of potential energy of a particle as a function of x, the x-coordinate of the region. It has been assumed that potential energy depends only on x. For all other values of x, U is zero, i.e., xlarr10 and xgt15 , U=0 . If the total mechanical energy of the particle is -40J , then it can be found in region
Figure shows the variation of potential energy of a particle as a function of x, the x-coordinate of the region. It has been assumed that potential energy depends only on x. For all other values of x, U is zero, i.e., xlarr10 and xgt15 , U=0 . If the particle is isolated and its total mechanical energy is 60J , then
The potential energy of a particle (U_(x)) executing SHM is given by
Potential energy of a particle varies with x according to the relation U(x)=x^(2)-4x .The point "x=2" is a point of
The potential energy of a particle varies with x according to the reltiaon U(x) =x^(2)-4x . The point x =2 is a point of
Potential energy curve U of a particle as function of the position of a particle is shown. The particle has total mechanical energy E of 3.0 joules. Then select correct alternative.
The potential energy of a particle of mass m is given by U=(1)/(2)kx^(2) for x lt 0 and U = 0 for x ge 0 . If total mechanical energy of the particle is E. Then its speed at x = sqrt((2E)/(k)) is
DC PANDEY-WORK, ENERGY & POWER-Level 2 Comprehension Based
