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calculateth resonance energy of N(2)O ...

calculateth resonance energy of `N_(2)O`
`Delta_(f)H^(-) of N_(2)O = 82 kJ mol ^(-1)`
bond energy of N=O = `607 kJmol ^(-1)`
bond energy of O=O = `498 kJ mol ^(-1)`
nond energy of N = N = `418 kJ mol^(-1)`
bond energy of N= N = `946 kJ mol ^(-1)`

A

`82 kJ mol ^(-1)`

B

`-88 kJ mol ^(-1)`

C

`- 82 kJ mol ^(-1)`

D

`+ 88 kJ mol ^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
b
`N equivN(g) + 1/2 O_(2)(g)to N=N=0`
calculated value of `Delta_(f)H^(Theta)=`
`Delta_(f)H^(-)=[BE( NequivN)+1/2BE(=O)]`
`[BE(N=N)+BE(N=O)]`
`[946+1/2(498)]- [418+607]=170 kJ mol^(-1)`
Respmace energy = observed `Delta_(f)H^(Theta)` - calculated `Delta_(f)H^(Theta)`
= 82 -170 =-88 kJ `mol^(-1)`
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Calculate the resonance energy of N_(2)O from the following data: DeltaH_(1)^(@) of N_(2)O = 82 kJ "mole"^(-1) . Bond energies N=N = 946 kJ "mole"^(-1) N=N = 418 kJ "mole"^(-1) O=O = 498 kJ "mole"^(-1) N=O = 607 kJ "mol"^(-1)

Calculate the resonance energy of N_(2)O from the following data: DeltaH_(1)^(@) of N_(2)O = 82 kJ "mole"^(-1) . Bond energies N=N = 946 kJ "mole"^(-1) N=N = 418 kJ "mole"^(-1) O=O = 498 kJ "mole"^(-1) N=O = 607 kJ "mole"^(-1)

Knowledge Check

  • Use the given data to calculate the resonance energy of N_(2)O.(Delta_(f)H^(ө) of N_(2)O=82kJmol^(-1)) Bond energy of N=O to607kJmol^(-1) Bond energy of O=O to498kJmol^(-1) bond energy of N=N to418kJmol^(-1) Bond energy of N-=Nto946kJmol^(-1) Choose the correct option.

    A
    82 kJ `mol^(-1)`
    B
    `-88kJ` `mol^(-1)`
    C
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    D
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  • Calculate the resonance energy of N_2O from the following data, Delta_fH ofN_2O is 82KJ mol^(-1)N-=N,946 KJ mol^(-1),N=N,418KJ mol^(-1), 0 = 0 , 498 KJ mol^(-1), N = 0,607KJ mol^(-1)

    A
    `+8.85 " KJ mol"^(-1)`
    B
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    C
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    Calcualate the resonance energy of N_(2)O from the following data : Delta_(f)H^(@) of N_(2)O= 82kJ mol^(-1) , Bond energies of N -= N , N = N , O=O and N=O bonds are 946, 418, 498 and 607 kJ mol^(-1) respectively.

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