`._(13)Al^(27)` is a stable isotope. `._(13)Al^(29)` is expected to disintegrate by

Options

A. `alpha` emission
B. `_(-1)^(0) beta` emission
C. Positron emission
D. Proton emission

Answer

B

Explanation

Since `._(13)^(27) Al` is stable isotope , `._(13)^(29)Al` has `(n)/(P)` ratio higher than required, it will disintegrate by `beta^(-)` emission and `(n)/(P)` ratio will decrease.
`._(13)^(29)Al rarr ._(14) si^(29)+._(-1)e^(0)`