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The van't Hof factor for 0.1 M Ba(NO(3))...

The van't Hof factor for 0.1 M `Ba(NO_(3))_(2)` solution is 2.74 . The degree of dissociation is

A

0.913

B

0.87

C

1

D

0.74

Text Solution

Verified by Experts

The correct Answer is:
B
`i=1+(n-1)alpha`
`2.74= 1+(3-1)alpha`
`alpha=0.87=87%`
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Colligative properties of a solution depend upon the number of moles of a solute dissolved and do not depend upon the nature of the solute. However, they are applicable only to dilute solutions in which the solutes do not undergo any association or dissociation. For solutes undergoing such changes, van't Hoff introduced a factor, called van't Hoff factor (i). This has helped not only to explain the abnormal molecular masses of such solutes in the solution but has also helped to calculate the degree of association or dissociation. The van't Hoff factor for 0.1 M Ba(NO_(3))_(2) solution is 2.74. The degree of dissociation is

The value of any colligative property of any electrolyte is determined experimentally, it is found to be higher than the theoretically calculated vallue using the usual expressions. This is because the electrolytes undergo dissociation in the solution. Similarly, in case of some substances association takes place, e.g., acetic acid in benzene and the experimental value of colligative value. The experimentally observed molar masses come out to be different than the theoretical values. These are called abnormal molar masses. In such cases, a correction factor, i, called van't Hoff factor is introduced which is a ratio of observed value of colligative property to calculated value when the solution behaves ideally. Knowing i, the degree of dissociation or association of the solute can be calculated. The van't Hoff factor for 0.1 M Ba(NO_(3))_(2) solution is 2.74. The degree of dissociation is

Knowledge Check

  • The van't Hoff factor for 0.1 M Ba(NO_(3))_(2) solution is 2.74 . The degree of dissociation is :

    A
    `91.3%`
    B
    `87%`
    C
    `100%`
    D
    `74%`

  • The van't Hoff factor for 0.1 M Ba(NO_(3))_(2) solution is 2.74 . The degree of dissociation is

    A
    `91.3%`
    B
    `87%`
    C
    `100%`
    D
    `74%`

  • The van't Hoff factor for 0.1 M Ba(NO_(3))_(2) solution is 2.74. The degree of dissociation is

    A
    `91.3%`
    B
    `87%`
    C
    `100%`
    D
    `74%`

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