If the enthalpy of formation of `HCl (g)` and `Cl^(-) (aq)` are -92.3 kJ/mole and -167.44 kJ/mol, find the enthalpy of solution of hydrogen chloride gas.

Answer

`-75.14` kJ/mole

Explanation

`HCl(g)+(aq) rarr H^(+) (aq) +Cl^(-) (aq)" "( :' DeltaH_(f H^(+) (aq))=0)`
`DeltaH=0-167.44+92.3=-75.14" kJ/mole"`