`N^(th)` level of `Li^(2+)` has the same energy as the ground state energy of the hydrogen atom. If `r_(N)` and `r_(1)` be the radius of the `N^(th)` Bohr orbit of `Li^(2+)` and first orbit radius of H atom respectively, then the ratio `(r_(N))/(r_(1))` is
A
9
B
`1//9`
C
3
D
None
Text Solution
Verified by Experts
The correct Answer is:
C
`E=(E_(0)Z^(2))/(n^(2))=E_(0)rArr n=Z=3, ` for Lithium ` r=(r_(0)n^(2))/(Z)=(r_(0).3^(2))/(3)=3r_(0)`
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