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A ball of mass m moving horizontally at ...

A ball of mass m moving horizontally at a speed v collides with the bob of a simple pendulum at rest. The mass of the bob is also m. If the collision is perfectly inelastic and both balls sticks, the height to which the two balls rise after the collision will be given by:

A

`(v^(2))/(8g)`

B

`(v^(2))/(2g)`

C

`(2v^(2))/(g)`

D

`(v^(2))/(g)`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • A ball of mass m moving at a speed v collides with another ball of mass 3m at rest. The lighter block comes to rest after collisoin. The coefficient of restitution is

    A
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  • A particle of mass m moving with speed u collides perfectly inelastically with another particle of mass 3 m at rest. Loss of KE of system in the collision is

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