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Derive an expression for the magnetic f...

Derive an expression for the magnetic field at the site of the nucleus in a hydrogen atom due to the circular motion of the electron Assume that the atom is in its ground state and the answer in terms of fundamental constants

A

`(mu_(0)e^(7)pim^(2))/(8epsilon_(0)^(3)h^(5))`

B

`(mu_(0)e^(5)pim^(2))/(8epsilon_(0)^(3)h^(5))`

C

`(mu_(0)e^(5)pim^(2))/(8epsilon_(0)^(3)h^(4))`

D

`(mu_(0)e^(7)pim^(2))/(8epsilon_(0)^(3)h^(4))`

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A
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Knowledge Check

  • Magnetic field at the center (at nucleus) of the hydrogen like atom ("atomic number" = z) due to the motion of electron in nth orbit is proporional to

    A
    `(n^(3))/(z^(5))`
    B
    `(n^(4))/(z)`
    C
    `(z^(2))/(n^(3))`
    D
    `(z^(3))/(n^(5))`

  • The radius of hydrogen atom, in its ground state, is of the order of

    A
    `10^(-8)` cm
    B
    `10^(-6)` cm
    C
    `10^(-5)` cm
    D
    `10^(-4)` cm

  • Magnetic moment due to the motion of the electron in nth energy of hydrogen atom is proportional to

    A
    n
    B
    `n^(0)`
    C
    `n^(5)`
    D
    `n^(3)`

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