Home
Class 12
PHYSICS
There are two fixed heavy masses of magn...

There are two fixed heavy masses of magnitude `M` of high density at a distance `2d` apart. On the axis, a small mass `m` moves in a circle of radius `R` in the `y-z` plane between the heavy masses. Find the velocity of the small particle.

Text Solution

AI Generated Solution

To find the velocity of the small mass \( m \) moving in a circle of radius \( R \) between two fixed heavy masses \( M \) separated by a distance \( 2d \), we can follow these steps: ### Step 1: Analyze the Forces Acting on the Small Mass The small mass \( m \) experiences gravitational forces due to both heavy masses \( M \). The net gravitational force will act downwards due to symmetry, as the horizontal components of the forces from both masses will cancel each other out. ### Step 2: Calculate the Gravitational Force The gravitational force \( F \) exerted by one mass \( M \) on the small mass \( m \) can be expressed using Newton's law of gravitation: \[ ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GRAVITATION

    FIITJEE|Exercise Solved problem (Objective)|15 Videos
  • GRAVITATION

    FIITJEE|Exercise Comprehension|13 Videos
  • GRAVITATION

    FIITJEE|Exercise Numerical based Question|2 Videos
  • GMP ASSESMENT

    FIITJEE|Exercise Numerical Based|61 Videos
  • HEAT AND TEMPERATURE

    FIITJEE|Exercise NUMERICAL BASES QUESTIONS|1 Videos

Similar Questions

Explore conceptually related problems

Two particles each of equal mass (m) move along a circle of radius (r) under the action of their mutual dravitational. Find the speed of each particle.

Two particles of equal mass (m) each move in a circle of radius (r) under the action of their mutual gravitational attraction find the speed of each particle.

Knowledge Check

  • If r represents the radius of the orbit of a satellite of mass m moving around a planet of mass M , the velocity of the satellite is given by

    A
    `v^(2)="g" (M)/(R)`
    B
    `v^(2)=(GMm)/(R)`
    C
    `v=(GM)/(r)`
    D
    `v^(2)=(GM)/(r)`
  • Centripetal acceleration of a particle of mass m moving in a circle of radius r is 4//r^(2) . What is the angular momentum of the particle ?

    A
    4 m/r
    B
    `4 m// sqrt(r)`
    C
    `2 m sqrt(r)`
    D
    2 m/r
  • Two point masses M are kept fixed on the x-axis at a distance a from the origin, another point mass m is moving in a circular path of radius R (in y - z plane) under the influence of gravitational force of attraction, then speed of m will be (Assume no forces are acting on m other than the gravitational forces by two M)

    A
    `sqrt((2GMR^(2))/((R^(2)+a^(2))^((3)/(2))))`
    B
    `sqrt((GMR^(2))/((R^(2)+a^(2))^((3)/(2))))`
    C
    `sqrt((3GMR^(2))/((R^(2)+a^(2))^((3)/(2))))`
    D
    `sqrt((5GMR^(2))/((R^(2)+a^(2))^((3)/(2))))`
  • Similar Questions

    Explore conceptually related problems

    Two particles of equel mass (m) move in a circle of radius (r ) under the action of their mutual gravitational attraction.Find the speed of each particle.

    Two particles of equal mass m_(0) are moving round a circle of radius r due to their mutual gravitational interaction. Find the time period of each particle.

    How much work is done in circulating a small object of mass m around a sphere of mass m in a circle of radius R.

    Two particles of mass M and m are moving in a circle of radii R and r. if their time period are the same, what will be the ratio of their linear velocities?

    A particle of mass m is ocated at a distance r from the centre of shell of mass M and radius R. The force between the shell and mass F (r ) . The plot of F(r ) ve r is :