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The choice of reducing agent for metal o...

The choice of reducing agent for metal oxide is decided by thermodynamic principles of metallurgy. `Delta G` must be negative. Ellingham diagram is a plot of `Delta_(f)G^(0)` vs T for the formation of oxides of various elements. All the plots slope upwards when temperature increases. Each plot is a straight line except when some change in phase takes place. A metal will reduce the oxide of other metals which lie above it in this diagram.
At a temperature below 1623 K. Al cannot reduce

A

FeO

B

CrO

C

MgO

D

NiO

Text Solution

Verified by Experts

The correct Answer is:
C

AI can.t reduce MgO as Mg is more electropositive.
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Ellingham diagrams are plots of DeltaG_(1)^(@) Vs T for the formation of

……………….diagrams normally consist of plots of triangle_(f)G^(0) vs T for the formation of oxides of common metals.

Knowledge Check

  • The choice of reducing agent for metal oxide is decided by thermodynamic principles of metallurgy. Delta G must be negative. Ellingham diagram is a plot of Delta_(f)G^(0) vs T for the formation of oxides of various elements. All the plots slope upwards when temperature increases. Each plot is a straight line except when some change in phase takes place. A metal will reduce the oxide of other metals which lie above it in this diagram. Delta G^(0) vs T plot in the Ellingham's diagram slopes downward for the reaction.

    A
    `Mg + (1)/(2)O_(2) rarr MgO`
    B
    `2Ag + (1)/(2) O_(2) rarr Ag_(2)O`
    C
    `C + (1)/(2) O_(2) rarr CO`
    D
    `CO + (1)/(2) O_(2) rarr CO_(2)`
  • The plot of Delta G versus temperature for the formation of oxides of elements is called

    A
    Ellingham diagram
    B
    Free energy curve
    C
    Entropy curve
    D
    Isobar
  • In Ellingham diagram, the slope of the curve of the formation metal oxide:

    A
    is mostly `+ve`
    B
    is mostly `-ve`
    C
    depends on the type of metal
    D
    depends on the formula of metal oxide
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