Statement -1 `I_(2) +I to I_(3)`
in above `.I_(2)` is lewis base and
Satement -2 Electron pair acceptor is lewis base

Options

A. statement -1 is true , statement -2 is true lewis base .
B. statement -1 is true statement -2 is true statement -2 is true , statement -2 is not a correct explanation for statement -1
C. statement-1 is true statement -2 si false
D. STATEMENT -1 IS FALSE , STATEMENT -2 IS FALSE

Explanation

To analyze the statements provided, we need to evaluate the definitions and characteristics of Lewis acids and bases.

### Step-by-Step Solution:

**Step 1: Analyze Statement 1**
- Statement 1 claims that \( I_2 \) is a Lewis base in the reaction \( I_2 + I^- \rightarrow I_3^- \).
- A Lewis base is defined as a species that donates an electron pair to form a covalent bond.

**Step 2: Determine the Role of \( I_2 \) in the Reaction**
- In the reaction, \( I_2 \) reacts with \( I^- \) to form \( I_3^- \).
- Here, \( I^- \) is a negatively charged ion and can donate an electron pair to \( I_2 \).
- Therefore, \( I_2 \) is actually accepting an electron pair from \( I^- \).

**Step 3: Conclusion for Statement 1**
- Since \( I_2 \) is accepting an electron pair, it acts as a Lewis acid, not a Lewis base.
- Thus, Statement 1 is **false**.

**Step 4: Analyze Statement 2**
- Statement 2 states that an electron pair acceptor is a Lewis base.
- According to the definition of Lewis acids and bases, a Lewis acid is the species that accepts an electron pair.

**Step 5: Conclusion for Statement 2**
- Since an electron pair acceptor is defined as a Lewis acid, Statement 2 is also **false**.

**Final Conclusion:**
- Both Statement 1 and Statement 2 are false.

### Answer:
- The correct option is: **Option 4: Statement 1 is false and Statement 2 is false.**

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