Home
Class 12
PHYSICS
An alpha is moving along a circle of rad...

An `alpha` is moving along a circle of radius R with a constant angular velocity `omega`. Point A lies in the same plane at a distance 2R from the centre. Point A records magnetic field produced by the `alpha`-particle. If the minimum time interval between two successive time at which A records zero magnetic field is t, the angular speed `omega`, in terms of t, is

A

`(2pi)/t`

B

`(2pi)/3t`

C

`pi/3t`

D

`pi/t`

Text Solution

Verified by Experts

The correct Answer is:
B
Point `A` shall record zero magnetic field (due to `alpha`-particle) when the `alpha`-particle is at position `P` and `Q` as shown in figure.The time taken by `alpha`-particle to go from `P` to `Q` is
`t=1/3(2pi)/omega` or `omega=(2pi)/(3t)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTRODYNAMICS

    RESONANCE|Exercise Exercise-2 PART-2|26 Videos

  • ELECTRODYNAMICS

    RESONANCE|Exercise Exercise-2 PART-3|18 Videos

  • ELECTRODYNAMICS

    RESONANCE|Exercise Exercise-1 PART-2|54 Videos

  • ELECTRO MAGNETIC WAVES

    RESONANCE|Exercise Exercise 3|27 Videos

  • ELECTROMAGNETIC INDUCTION

    RESONANCE|Exercise A.l.P|19 Videos

Similar Questions

Explore conceptually related problems

A source is moving on a circle of radius 3m with constant angular velocity omega = 5 rad s^(-1) . If the observer is at a distance 5 cm from the centre of the circle, the time interval between the maximum and minimum frequency received by the observer is

A conducting ring of radius r having charge q is rotating with angular velocity omega about its axes. Find the magnetic field at the centre of the ring.

Knowledge Check

  • A particle moves along a circle of radius R with a constant angular speed omega . Its displacement (only magnitude) in time t will be

    A
    `omega t`
    B
    `2R cos omega t`
    C
    `2 R sin omega t`
    D
    `2R "sin" (omega t)/(2)`

  • A particle moves along a circle of radius R with a constant angular speed omega . Its displacement (only magnitude) in time t will be

    A
    `omegat`
    B
    `2R cos omega t`
    C
    `2R sin omegat`
    D
    `2Rsin. (omegat)/2`

  • A particle of mass m is moving along a circle of radius r with a time period T . Its angular momentum is

    A
    `(2pimr)/T`
    B
    `(4pimr)/T`
    C
    `(2pimr^(2))/T`
    D
    `(4pimr^(2))/T`

    • Similar Questions

    Explore conceptually related problems

    A ring rotates with angular velocity omega about an axis in the plane of the ring which passes through the center of the ring. A constant magnetic field B exists perpendicualr to the plane of the ring . Find the emf induced in the ring as a function of time.

    The magnitude of displacement of a particle moving in a circle of radius a with constant angular speed omega varries with time t is

    a conducting disc of radius R roatates about its axis when an angular velocity omega .Then the potential difference between the centre of the disc and its edge is (no magnetic field is present ):

    A gramophone record of mass M and radius R is rotating at an angular velocity omega A coin of mass is gently placed on the record at a distance r = (R )/(2) from its centre. The new angular velocity of the system is

    A point mass moves along a circle of radius R with a constant angular acceleration alpha . How much time is needed after motion begins for the radial acceleration of the point mass to be equal to its tangential acceleration ?

    Home
    Profile