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A charge of 1 coulumb is placed is one e...

A charge of `1` coulumb is placed is one end of a non-conducting rod of length `0.6m`.The rod is rotated in a vertical plane about a horizontal axis passing through the other end of the rod with an angular velocity `10^(4)pi rad//sec`.Find the magnetic field at a point on the axis of rotation of a distance of `0.8m` from the centre of the path is `Npixx10^(-4) T`,then find value of `N`.

Text Solution

Verified by Experts

`vecB=mu_(0)/(4pi) q((vecvxxvecr)/r^(3))`
`B=mu_(0)/(4pi)(qv)/((x^(2)+R^(2)))=(10^(-7)xx1xx0.6xx10^(4)pi)/1=6pixx10^(-4) T`
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A charge of 1 coul. is placed at one end of a non-conducting rod of length 0.6m. the rod is rotated in a vertical plane about a horizontal axis passing through the other end of the rod with angular frequency 10^(4) pi "radian/sec" . Find the magnetic field at a point on the axis ofrotation at a distance of 0.8 from the centre of the path. Now half of the charge is removed from one end and placed on the other end. The rod is rotated in a vertical plane about horizontal axis passing through the mid-point of the rod with the same angnlar frequency. Calculate the magnetic field at a point on the axis at a distance of 0.4m form the centre of the rod.

Knowledge Check

  • A uniform metal rod is rotated in horizontal plane about a vertical axis passing through its end at uniform rate. The tension in the rod is

    A
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    B
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    D
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