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The number of oxygen atoms present in 24...

The number of oxygen atoms present in 24.5 gm of `H_(3)PO_(4)` is equal to (P = 31)

A

Number of electrons present in 1.6 gm methane `(CH_(4))`

B

Number of molecule of `CO_(2)` present in 22 gm `CO_(2)`

C

Number of moles of proton present in `N_(A) gm`-atom of hydrogen.

D

Number of total atoms present in `(4)/(3)` mol of `CO_(2)`

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Knowledge Check

  • The number of atoms present in 10 gms of CaCO_(3) are

    A
    `5N^(3)`
    B
    0.5N
    C
    5
    D
    N

  • The number of atoms present in 0*1 mole of P_(4) (at. Mass = 31) are

    A
    `2*4xx10^(24)` atoms
    B
    same as in `0*05` mol of `S_(8)`
    C
    `6*02xx10^(22)`
    D
    same as in `3*1` g of phosphorus

  • The number of bridge oxygen atoms present in both P_(4)O_(6) and P_(4)O_(10) are respectively

    A
    4, 6
    B
    4, 4
    C
    6, 6
    D
    6, 4

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