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A particle is moving along a circular pa...

A particle is moving along a circular path ofradius R in such a way that at any instant magnitude of radial acceleration & tangential acceleration are equal. 1f at t = 0 velocity of particle is `V_(0)`. Find the speed of the particle after time `t=(R )//(2V_(0))`

Text Solution

Verified by Experts

The correct Answer is:
`2V_(0)`
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Knowledge Check

  • A particle is moving along a circular path of radius of R such that radial acceleration of particle is proportional to t^(2) then

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    Speed of particle is constant
    B
    Magnitude of tangential acceleration of particle is constant
    C
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    `(R)/(u_(0))(1-e^(-2pi))`
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