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The area of the parallelogram represente...

The area of the parallelogram represented by the vectors `vecA=2hati+3hatj` and `vecB=hati+4hatj` is

A

14 unit

B

7.5unit

C

10unit

D

5unit

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • Area of the parallelogram formed by vectors vecA = hati + 2hatj+ 4 hatk and vecB= 3 hati - 2hatj is :

    A
    `4sqrt(17) "unit"`
    B
    `2sqrt(17) "unit"`
    C
    `17sqrt(2) "unit"`
    D
    `17sqrt(3) "unit"`

  • Diagonals of a parallelogram are respresented by vectors vecA = 5hati - 4hatj + 3hatk and vecB = 3hati +2hatj - hatk . Area of the parallelogram is :

    A
    `sqrt(171) "units"`
    B
    `sqrt(72) "units"`
    C
    `sqrt(72) "units"`
    D
    72 units

  • If vecA=4hati+6hatj and vecB=2hati+3hatj . Then

    A
    `vecA.vecB=29`
    B
    `vecAxxvecB=vec0`
    C
    `(|vecB|)/(|vecA|)=2/1`
    D
    angle between `vecA` and `vecB` is `30^@`

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