Two elelctric bulbs P and Q have their resistance in the ratio of 1: 2. They are connected in series across a battery. Find the ratio of the power dissipation in these bulbs.

Explanation

Formula staling that current are equal Ratio powers
Power =FR
( The current in the two bulbs , is the same as they are connected in series.
`( P_1)/( P_2) =( I^(2) R_1) /( I^(2) R_2) =(R_1)/(R_2) `
` (1)/(2) `