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Define electric flux. Is it a scalar or ...

Define electric flux. Is it a scalar or a vector quantity?
A point charge q is at a distance of d/2 directly above the centre of a square of side , as shown in the figure .Use Gauss, law to obtain the expression for the electric flux through the square.

Text Solution

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Electric flux through a given surface is defined as the dot product of electric field and area vector over than surface
Altermatively `phi =int_4oversetto Ed oversetto S `
Also accept
Electric flux. Through a surface equals the surface integral of the electric field over that surface It is a scalar quantity
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Contructing a cube of side.d. so that charge .q. gets placed within of this cube ( Gaussian surface ) Accroding to Gauss .s law the Electric flux.
`phi =("Charge enclosed ")/( in _0) `
This is the total flux through all the six faces of the cube. Hence electric flux through the square.
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(a) Define electric flux. Is is the scalar or a vector quantity? A point charge q is at a distance of d//2 directly above the centre of a square of side d, as shown in the figure. Use Gauss's law to obtain the expression for the electric flux through the square. (b) If the point charges is now moved to a distance 'd' from the centre of the square and the side of the square is doubled, explain how the electric flux will be affected.

Define electric flux, Is it a scalar or a vector quantity? A point charg q is at a distance of (d)/(2) directly above the centre of a square of side 'd' Use Gauss' law to obtain the expression for the electric flux through the square. (b) If the point charge is now moved to a distance 'd' from the centre of the square and the side of the square is doubled , explain how the electric flux will be affected.

Knowledge Check

  • A point charge q is placed at a distance a//2 directly above the centre of a square of side a . The electric flux through the square is

    A
    `(q)/(epsilon_(0))`
    B
    `(q)/(piepsilon_(0))`
    C
    `(q)/(4epsilon_(0))`
    D
    `(q)/(6epsilon_(0))`
  • A point charge q is placed at a distance (a)/(2) directly above the centre of a horizontal square of side 'a' and another point charge -q is placed at a distance 'a' directly below one of its (the square's) corners. The electric flux through the square is :

    A
    `(q)/(6 in_(0))`
    B
    `(q)/(8in_(0))`
    C
    `(q)/(24in_(0))`
    D
    `(5q)/(24in_(0))`
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