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A maximum current point 0.5 mA can be pa...

A maximum current point 0.5 mA can be passed through a galvanometer of resistance 20 `Omega` . The resistance to be connected in series to convert it in to voltmeter of range 0-5V.is

Text Solution

Verified by Experts

R = G (n-1) , where `n = (V)/(V_g)`
` V = 5V, V_g = i_(g) G = 0.5 xx 10^(-3) xx 20 = 10^(-2) V`
` therefore n = 500 " and " R = 20 (500 -1) = 9980 Omega `
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Knowledge Check

  • A maximum current point 0.5mA can be passed through a galvanometer of resistance 20Omega . The resistance to be connected in series to convert it in the voltmeter of range 0-5V is

    A
    `980Omega`
    B
    `9980Omega`
    C
    `990Omega`
    D
    `9990Omega`
  • The range of voltmeter of resistance 300 Omega is 5 V. The resistance to be connected to convert it into an amineter of range 5 A is

    A
    1`Omega` in series
    B
    1`Omega`in parallel
    C
    0.1`Omega` in series
    D
    0.1`Omega` in parallel
  • The range of voltmeter of resistance 300 Omega is 5 V. The resistance to be connected to convert it into an ammeter of range 5 A is

    A
    ` 1 Omega "in series"`
    B
    `1 Omega "in parallel"`
    C
    `0.1 Omega "in series"`
    D
    `0.1 Omega "in parallel"`
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