A maximum current point 0.5 mA can be passed through a galvanometer of resistance 20 `Omega` . The resistance to be connected in series to convert it in to voltmeter of range 0-5V.is

Explanation

R = G (n-1) , where `n = (V)/(V_g)`
` V = 5V, V_g = i_(g) G = 0.5 xx 10^(-3) xx 20 = 10^(-2) V`
` therefore n = 500 " and " R = 20 (500 -1) = 9980 Omega `