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A paramagnetic sample shows a net magnet...

A paramagnetic sample shows a net magnetisation of `8Am^-1` when placed in an external magnetic field of `0*6T` at a temperature of `4K`. When the same sample is placed in an external magnetic field of `0*2T` at a temperature of `16K`, the magnetisation will be

A

`32/3Am^(-1)`

B

`2/3Am^(-1)`

C

`6Am^(-1)`

D

`2.4Am^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B

As curie law explains, we can deduce a formula for the relation between magnetic field induction, temperature and magnetisation.
i.e.,
`I("magnetisation")oo(B("magnetic field induction"))/(t("temperature in kelvin"))`
`rArrI_(2)/I_(1)=B_(2)/B_(1)xxt_(1)/t_(2)`
Let us suppose, here `I_(1)=8Am^(-1)`
`B_(1)=0.6T,t_(1)=4K`
`B_(2)=0.2T,t_(2)=16K`
`I_(2)=?`
`rArr0.2/0.6xx4/16=I_(2)/8`
`rArrI_(2)=8xx1/12=2/3Am^(-1)`
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Knowledge Check

  • A paramagnetic sample shows a net magnetization of 8 Am^(-1) when placed in an external magnetic field of 0.6 T at a temperature of 4 K When the same sample is placed in an external magnetic field of 0.2 T at a temperature of 16 K, the magnetization will be

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    D
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  • A paramagnetic sample shows a net magnetisation of 0.8A-m^(-1) when plced in an external mgnetic field of 0.8T at a temperature of 5K. Whent the same sample is placed in an external magnetic field of 0.4T at temperature of 20K, the magnetisation will be

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    `0.8Am^(-1)`
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