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The energy required to excition an elect...

The energy required to excition an electron from `n=2` to `n=3` energy state is `47.2eV`. The charge number of the nucleus, around which the electrons revolving will be

A

5

B

10

C

15

D

20

Text Solution

Verified by Experts

The correct Answer is:
A
` E = E_(3) - E_(2) = (13.6 Z^2)/(4) -(13.6 Z^2)(9) =47.2 rArr Z =?`
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The energy required to excite an electron from n = 2 to n = 3 energy level is 47.2 eV. The charge of Nucleus around which the electron is revolving is ne, find n. (in terms of no. of protons)

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Knowledge Check

  • The energy (in eV) required to excite an electron from n = 2 to n = 4 state in hydrogen atom is

    A
    `-0.85`
    B
    `+4.25`
    C
    `-3.4`
    D
    `+2.55`

  • The energy ( in eV ) required to excite an electron from n = 2 to n = 4 state in hydrogen atom is

    A
    `-0.85`
    B
    `+4.25`
    C
    `-3.4`
    D
    `+2.55`

  • The energy required to remove an electron in a hydrogen atom from n = 10 state is

    A
    `13.6 eV`
    B
    `1.36 eV`
    C
    `0.136 eV`
    D
    `0.0136 eV`

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