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The maximum wavelength of Brackett serie...

The maximum wavelength of Brackett series of hydrogen atom will be _____`A^(@)`

A

`35,890`

B

`14,440`

C

`62,160`

D

`40,477`

Text Solution

Verified by Experts

The correct Answer is:
D
`RZ^(2) ((1)/(n_(1)^(2))-(1)/(n_(2)^(2))=(1)/(lambda))` Where `n_(1)=4, n_(2) =5`.
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Knowledge Check

  • The maximum wavelength of Lyman series is

    A
    `C/R`
    B
    `1/R^2`
    C
    `(4)/(3R)`
    D
    `(1)/(CR)`

  • Balmer series of hydrogen atom lies in

    A
    microwave region
    B
    visible region
    C
    ultraviolet region
    D
    infrared region

  • What would be maximum wavelength for Brackett series of hydrogen-spectrum?

    A
    ` 74583 Å`
    B
    `22790Å`
    C
    `40519Å`
    D
    `18753Å`

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