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The maximum wavelength of Brackett serie...

The maximum wavelength of Brackett series of hydrogen atom will be _____`A^(@)`

A

`35,890`

B

`14,440`

C

`62,160`

D

`40,477`

Text Solution

Verified by Experts

The correct Answer is:
D
`RZ^(2) ((1)/(n_(1)^(2))-(1)/(n_(2)^(2))=(1)/(lambda))` Where `n_(1)=4, n_(2) =5`.
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