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In a p-n junction the depletion region i...

In a `p-n` junction the depletion region is `400 nm` wide and electric field of `5 xx 10^(5) Vm^(-1)` exists in it. The minimum energy of a conduction electron, which can diffuse from n-side to the p-side is.

A

4eV

B

5eV

C

`0.4eV`

D

`0.2eV`

Text Solution

Verified by Experts

The correct Answer is:
D
`W=Vq=Edq`
`=5xx10^(5)xx400xx10^(-9)xx1.6xx10^(-19)J`
`=(5xx10^(5)xx400xx10^(-9)xx1.6xx10^(-19)J)/(1.6xx10^(-19))eV`
`=2000X10^(-4) eV=0.2eV`
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Knowledge Check

  • The width of the depletion region in a p-n junction diode is 400 nm and an intense electric field of 8 xx 10^5 V/m exists in it. What is the kinetic energy which a conduction electron must have in order to diffuse from then region to p region?

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