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In a half wave rectifier output is taken...

In a half wave rectifier output is taken across a `90 ohm` load resistor. If the resistance of diode in forward biased condition is `10 ohm`, the efficiency of rectification of `ac` power into `dc` power is.

A

`40.6%`

B

`81.2%`

C

`73.08%`

D

`36.54%`

Text Solution

Verified by Experts

The correct Answer is:
D
`eta=(0.406R_(L))/(r_(f)+R_(L))`
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