245 g of iodine and 142 g of chlorine are made to react completely to given a mixture of `ICl` and `ICl_(3)` .How many moles of each are formed ?

Options

A. 0.1 mole of IC l and 0.1 mole of `ICI_(3)`
B. 1 mole of I Cl and 1 mole of `ICL_(3)`
C. 0.5 mole of IC l and 0.1 mole of `ICl_(3)`
D. 0.5 mole of IC l and 0.1 mole of IC l mole of `ICl_(3)`

Answer

B

Explanation

Both reasctants are completely consumed, hence, both are limiting.
`I_(2) + 2Cl_(2) to ICl+ ICl_(3)`
254g or 1 mole `I_(2)` and 142 g or `Cl_(2)` will react to given 1 mole Icl and 1 mole `IC l_(3)`.]