What mass of magnesium hydroxide is required to neutralize 125 mL of `0.136` M hydrochloric acid solution?
`{:("Substance","Molar Mass"),("MG"(OH)_(2),"58.33 gmol"^(-1)):}`

Answer

b

Explanation

`Mg(OH)_(2)+2HCl to MgCl_(2)+2H_(2)O`
Number of moles of HCl=`(MV)/(1000)=(0.136xx125)/(1000)=0.017`
2 mole HCl is neutralized by 58.33g of Mg `(OH)_(2)`
0.017 mole of HCl will be neutralized by `(58.33)/(2)xx0.017g` of `Mg(OH)_(2)` =0.496g