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What mass of magnesium hydroxide is requ...

What mass of magnesium hydroxide is required to neutralize 125 mL of `0.136` M hydrochloric acid solution?
`{:("Substance","Molar Mass"),("MG"(OH)_(2),"58.33 gmol"^(-1)):}`

Text Solution

Verified by Experts

The correct Answer is:
b
`Mg(OH)_(2)+2HCl to MgCl_(2)+2H_(2)O`
Number of moles of HCl=`(MV)/(1000)=(0.136xx125)/(1000)=0.017`
2 mole HCl is neutralized by 58.33g of Mg `(OH)_(2)`
0.017 mole of HCl will be neutralized by `(58.33)/(2)xx0.017g` of `Mg(OH)_(2)` =0.496g
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Knowledge Check

  • What mass of magnesium hydroxide is required to neutralise 125 mL of 0.136 M HCl solution ? ("Substance")/(Mg(OH)_(2)) " " ("Molar mass")/(58.33 " g mol"^(-1))

    A
    0.248 g
    B
    0.496 g
    C
    0.992 g
    D
    1.98 g

  • The volume of 0.1M Ca(OH)_(2) required to neutralize 10 mL of 0.1 N HCl

    A
    10 mL
    B
    20 mL
    C
    5 mL
    D
    15 mL

  • What mass of NaHCO_(3) (M=84.0) is required to completely neutralize 25.0 mL of 0.125 M H_(2)SO_(4) ?

    A
    0.131 g
    B
    0.262g
    C
    0.525g
    D
    1.05g

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