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Reaction of Br(2) with Na(2)CO(3) in aqu...

Reaction of `Br_(2)` with `Na_(2)CO_(3)` in aquesous solution gives sodium bromide bromate with evolution of `CO_(2)` gas. The number of sodium bromide molecules involved in the balanced chemical equation is:

Text Solution

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`3Na_(2)CO_(3)+3Br_(2) to 5NaBr+NaBrO_(3)+3CO_(2)`
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Knowledge Check

  • Ethyl magnesium bromide reacts with solid CO_(2) to give

    A
    Ethanoic acid
    B
    Methanoic acid
    C
    Propanoic acid
    D
    butanoic acid

  • To balance the reaction Na+O_2rarrNa_2O the number of sodium and disodium oxide are

    A
    2 and 2 respectively
    B
    4 and 2 respectively
    C
    2 and 4 respectively
    D
    3 and 5 respectively

  • When SO_(2) is passed through sodium carbonate solution, then CO_(2) gas is liberated. This is because

    A
    `CO_(2)` is more volatile than `SO_(2)`
    B
    `CO_(2)` has a lower molecular weight than `SO_(2)`
    C
    `SO_(2)` is a stronger acid than `CO_(2)`
    D
    `CO_(2)` is a stronger acid than `SO_(2)`

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