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In which of the following compounds , th...

In which of the following compounds , the nitrogen atom exhibits negative oxidation state?

A

Sodium nitrate

B

NO

C

Sodium azide

D

Sodium nitrite

Text Solution

AI Generated Solution

The correct Answer is:
To determine in which of the following compounds the nitrogen atom exhibits a negative oxidation state, we will analyze each compound one by one. ### Step-by-Step Solution: 1. **Identify the Compounds**: The compounds we need to analyze are: - Sodium Nitrate (NaNO3) - Nitric Oxide (NO) - Sodium Azide (NaN3) - Sodium Nitrite (NaNO2) 2. **Analyze Sodium Nitrate (NaNO3)**: - Sodium (Na) has an oxidation state of +1. - Oxygen (O) typically has an oxidation state of -2. There are 3 oxygen atoms, contributing a total of -6. - Let the oxidation state of nitrogen (N) be \( x \). - The overall charge of the compound is 0, so we set up the equation: \[ +1 + x + (-6) = 0 \] \[ x - 5 = 0 \implies x = +5 \] - **Conclusion**: Nitrogen in NaNO3 is in the +5 oxidation state. 3. **Analyze Nitric Oxide (NO)**: - Oxygen (O) has an oxidation state of -2. - Let the oxidation state of nitrogen (N) be \( x \). - The overall charge of the compound is 0, so we set up the equation: \[ x + (-2) = 0 \] \[ x - 2 = 0 \implies x = +2 \] - **Conclusion**: Nitrogen in NO is in the +2 oxidation state. 4. **Analyze Sodium Azide (NaN3)**: - Sodium (Na) has an oxidation state of +1. - Let the oxidation state of nitrogen (N) be \( x \) for each nitrogen atom. - There are 3 nitrogen atoms, so the equation becomes: \[ +1 + 3x = 0 \] \[ 3x = -1 \implies x = -\frac{1}{3} \] - **Conclusion**: Each nitrogen in NaN3 has an oxidation state of -1/3. This indicates that nitrogen exhibits a negative oxidation state. 5. **Analyze Sodium Nitrite (NaNO2)**: - Sodium (Na) has an oxidation state of +1. - Oxygen (O) has an oxidation state of -2. There are 2 oxygen atoms, contributing a total of -4. - Let the oxidation state of nitrogen (N) be \( x \). - The overall charge of the compound is 0, so we set up the equation: \[ +1 + x + (-4) = 0 \] \[ x - 3 = 0 \implies x = +3 \] - **Conclusion**: Nitrogen in NaNO2 is in the +3 oxidation state. ### Final Conclusion: The only compound where nitrogen exhibits a negative oxidation state is **Sodium Azide (NaN3)**.
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Knowledge Check

  • In which of the following compound does hydrogen exhibit a negative oxidation state:

    A
    `LiH`
    B
    `H_(2)O`
    C
    `HCl`
    D
    none of these
  • In which of the following compounds, nitrogen exhibits the highest oxidation state?

    A
    `N_(3)H`
    B
    `NH_(2)OH`
    C
    `N_(2)H_(4)`
    D
    `NH_(3)`
  • In which of the following compounds, nitrogen exhibits highest oxidation state ?

    A
    `N_(3)H`
    B
    `NH_(2)OH`
    C
    `N_(2)H_(4)`
    D
    `NH_(3)`
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