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Three boys A,B and C are situated at the...

Three boys A,B and C are situated at the vertices of an equilateral triangle of side d at t=0. Each of the boys moves with constant speed v. A always moves towards C and C towards A, At what time and where they meet each other?

Text Solution

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By symmetry they will meet at the centroid of the triangle. Approaching velocity of A and B towards each other is `v+v cos 60^(@)` and they cover distance d when they meet. So that time taken.
`therefore t=(d)/(v+vcos 60^(@))=(d)/(v+(v)/(2))=(2d)/(3v)`
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Knowledge Check

  • Three particles A, B and C are situated at the vertices of an equilateral triangle ABC of side d at time t=0. Each of the particles moves with constant speed v. A always has its velocity along AB, B along BC and C along CA. At what time will the particles meet each other?

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  • Three particles A,B and C and situated at the vertices of an equilateral triangle ABC of side of length l at time t=0 ,Each of the particles move with constant speed u . A always has its velocity along AB, B along BC and C along CA .

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