The distance x of a particle moving in one dimensions, under the action of a constant force is related to time t by the equation, `t=sqrt(x)+3`, where x is in metres and t in seconds. Find the displacement of the particle when its velocity is zero.

Options

A. 2m
B. 4m
C. 5m
D. zero

Answer

D

Explanation

`t=sqrt(x)+3rArrsqrt(x)=t-3`
`x=(t-4)^(2)=t^(2)-6t+9`
`x=t^(2)-6t+9`
`v=(dx)/(dt)=2t-6`
for `v=0,2t-6=0rArrt=3` sec
at t=3 sec
`x=(3-3)^(2)=0`