Calculate the work done by `0.1` mole of a gas at `27^(@)C` to double its volume at constant pressure `(R = 2 cal mol^(-1)K^(-1))`

Explanation

To calculate the work done by 0.1 mole of a gas at 27°C to double its volume at constant pressure, we can follow these steps:

### Step 1: Identify the Given Data
- Number of moles (n) = 0.1 moles
- Initial temperature (T1) = 27°C = 27 + 273 = 300 K
- Final volume (V2) = 2 * V1 (since the volume doubles)
- Gas constant (R) = 2 cal mol^(-1) K^(-1)

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