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Internal energy of two moles of an idea...

Internal energy of two moles of an ideal gas at temperature of `27^(@)C` is `1200 R`. Then find the molar specific heat of the has at constant pressure ?

Text Solution

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`U = 1200 R = n CvT`
`1200 R = 2 Cv xx 400`
`C_(v) = (3)/(2)R " " :. " " C_(P) = R+(3)/(2)R = 2.5 R`
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Knowledge Check

  • Molar specific heat of a monatomic gas at constant pressure is

    A
    5/2 R
    B
    3/2 RT
    C
    7/2 R
    D
    R

  • If the molar specific heat capacity at constant volume of an ideal gas is C_(v) = 3/2 R , then what is the corresponding molar specific heat capacity of the ideal gas at constant pressure ?

    A
    `1/2 R`
    B
    `5/2 R`
    C
    `7/2 R`
    D
    `9/2 R`

  • One mole of an ideal gas at an initial temperature of T K does 6R joules of work adiabatically. If the ratio of specific heat s of this gas at constant pressure and at constant volume is 5/3, the final temperature of gas will be

    A
    `(T + 2.4) K`
    B
    `(T -2.4) K`
    C
    `(T + 4) K `
    D
    `(T-4)K`

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