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What is DeltaU when 2.0 mole of liqu...

What is `DeltaU` when 2.0 mole of liquid water vaporise at `100^(@)C ` ? The heat of vaporistaion , `DeltaH` vap. of water at `100^(@)C` is `40.66 kJ mol^(-1)`.

Text Solution

Verified by Experts

`Delta U= DeltaH-(P_(2)V_(2)-P_(1)V_(1)) ( because V_(2) gt gt V_(1))`
`Delta H-(P_(2)V_(2)) rArrDeltaH-nRT`
`Delta U= 40.66xx2-(2xx8.314xx373)/(1000)=75.12 KJ`
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Knowledge Check

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