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DeltaH=30kJmol^(-1), DeltaS=75J//K//mol....

`DeltaH=30kJmol^(-1), DeltaS=75J//K//mol. "find boiling temperature at" 1atm: `

A

400K

B

300K

C

150 K

D

425 K

Text Solution

Verified by Experts

The correct Answer is:
A
Given that , ` DeltaH_("vaps") = 30` KJ/mol =`30xx10^(3)` J/mol.
`" "DeltaS_("vaps") = 75` J/mol.
We know that, `DeltaS =(DeltaH_("vaps"))/(T_(B.P))`
`therefore DeltaH =TDeltaS implies 30 xx 10^(3) = T xx 75`.
T=400 k.
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