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In (x-y) plane motion of particle it's (...

In `(x-y)` plane motion of particle it's `(x-y)` coordinate depends on time given by `[(t^(2)-4),4t]`, find velocity when particle crosses y-axis

A

`(2hat(i)+2hat(j))`

B

`8hat(J)`

C

`(4hat(i)+4hat(j))`

D

`4hat(i)`

Text Solution

Verified by Experts

The correct Answer is:
C

`vec(r)=(t^(2)-4)hat(i)+4that(j)`
`t^(2)-4=0`
t = 2sec
`vec(v)=(2that(i)+4hat(j))`
`vec(v)=(4hat(i)+4hat(j))`
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Knowledge Check

  • A particle moves along x-axis and its displacement at any time is given by x(t) = 2t^(3) -3t^(2) + 4t in SI units. The velocity of the particle when its acceleration is zero is

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