In a series RL circuit with `L=(175)/(11)mH` and `R=12Omega` and AC source of emf `e=130sqrt(2)V`, 50Hz is applied. Find the circuit impedance and phase difference of EMF and current in circuit.
In a simple circuit with resistance, phase between AC emf and AC current is
In a series L-R circuit (L=35 mH and R=11 Omega) , a variable emf source (V=V_(0) sin omega t) of V_(rms)=220V and frequency 50 Hz is applied. Find the current amplitude in the circuit and phase of current with respect to voltage. Draw current-time graph on given graph (pi=22/7) .
An LCR series circuit with L = 100 mH, C = 100 muF, R = 120 Omega is connected to an AC source of emf epsilon = (30 V) sin (100s^(-1))t . Find the impedane, the peak current and the resonant frequency of the circuit.
The phase angle between e.m.f. and current in LCR series ac circuit is
The alternating emf of e=e_(0) sin omegat is applied across LR series circuit. The impedance and phase angle between current and voltage is
Fig. show a series LCR circuit with L = 0.1 H l, X_(C ) = 14 Omega and R = 12 Omega connected to a 50 Hz, 200 V source. Calculate (i) current in the circuit and (ii) phase angle between current and voltage. Take pi = 3
In an electrical circuit R,L,C and an AC voltage source are all connected in series. When L is removed from the circuit, the phase difference between the voltage and the current in the circuit is pi//3 . If instead, C is removed from the circuit, difference the phase difference is again pi//3 . The factor of the circuit is
In a series L - C circuit, if L = 10^(-3) H and C = 3xx10^(-7) F is connected to a 100 V-50 Hz a.c. Source, the impedance of the circuit is
