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In a series RL circuit with L=(175)/(11)...

In a series RL circuit with `L=(175)/(11)mH` and `R=12Omega` and AC source of emf `e=130sqrt(2)V`, 50Hz is applied. Find the circuit impedance and phase difference of EMF and current in circuit.

A

`14,14A, 30^(@)`

B

`10sqrt2A, "tan"^(-1)(5)/(12)`

C

`10A, "tan"^(-1)(5)/(12)`

D

`20A, "tan"^(-1)(5)/(12)`

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • In a simple circuit with resistance, phase between AC emf and AC current is

    A
    `0^(@)`
    B
    `90^(@)`
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    0 to `pi//2`
    B
    `pi//4`
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    `pi//2`
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    `pi`

  • The alternating emf of e=e_(0) sin omegat is applied across LR series circuit. The impedance and phase angle between current and voltage is

    A
    `sqrt(R^(2)+X_(L)^(2)),"tan"^(-1)((X_(L))/(R))`
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