An `L-C-R` series circuit with `100Omega` resistance is connected to an `AC` source of `200V` and angular frequency `300rad//s`. When only the capacitance is removed, the current lags behind the voltage by `60^@`. When only the inductance is removed the current leads the voltage by `60^@`. Calculate the current and the power dissipated in the `L-C-R` circuit
A series L-C-R circuit with a resistance of 500 Omega is connected to an a.c. source of 250 V. When only the capacitance is removed, the current lags behind the voltage by 60^(@) . When only the inductance is removed, the current leads the voltage by 60^(@) . What is the impedance of the circuit?
In an LCR circuit R=100 ohm . When capacitance C is removed, the current lags behind the voltage by pi//3 . When inductance L is removed, the current leads the voltage by pi//3 . The impedence of the circuit is
An L-C-R series circuit with R=100Omega is connected to a 200V , 50Hz a.c. source .When only the capacitance is removed, the voltage leads the current by 60^(@) and when only the inductance is removed, the current leads the voltage by 60^(@) . The current in the circuit is
An LCR series circuit with R = 100 Omega is connected to a 300V, 50Hz a.c. source. If the capacitance is removed from the circuit then the current lags behind the voltage by 30^(@) . But if the inductance is removed form the circuit the current leads the voltage by 30^(@) . What is the current in the circuit?
An LCR circuit contains resistance of 110 Omega and a supply of 220 V at 300 rad/s angular frequency. If only capacitance is removed from the circuit, current lags behind the voltage by 45^(@) . If on the other hand, only inductor is removed the current leads by 45^(@) with the applied voltage. The rms current flowing in the circuit will be :
