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Calculate the pH of 0.10 M solution of N...

Calculate the pH of 0.10 M solution of `NH_4CI` . The dissociation constant `(K_b) "of" NH_3 "is" 1.8 xx 10^(-5)` .

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To calculate the pH of a 0.10 M solution of ammonium chloride (NH₄Cl), we can follow these steps: ### Step 1: Identify the nature of the salt Ammonium chloride (NH₄Cl) is a salt formed from a strong acid (HCl) and a weak base (NH₃). When dissolved in water, it dissociates into NH₄⁺ and Cl⁻ ions. ### Step 2: Determine the relevant equilibrium The ammonium ion (NH₄⁺) can undergo hydrolysis in water: \[ \text{NH}_4^+ + \text{H}_2\text{O} \rightleftharpoons \text{NH}_3 + \text{H}_3\text{O}^+ \] ...
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Calculate the pH of 0.10 M solution of NH_(4)Cl . The dissociation constant (K_(b)) of NH_(3) is 1.6xx10^(-5) .

Calculate the pH of 0.10 M solution of Nh_(4)Cl. The dissociation constant (K_(b)) of NH_(3) is 1.8xx10^(-5)

Knowledge Check

  • The pH of a 0.1M solution of NH_(4)Oh (having dissociation constant K_(b) = 1.0 xx 10^(-5)) is equal to

    A
    `10`
    B
    `6`
    C
    `11`
    D
    `12`
  • What is pH of 0.02 M solution of ammonium chloride at 25^(@) C ? K_(b) (NH_(3)) = 1.8 xx 10^(-5) .

    A
    `5.477`
    B
    `8.523`
    C
    7
    D
    `4.8732`
  • Similar Questions

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    The pH of a 0.1 M solution of NH_4Cl is 5:13. Find the dissociation constant of NH_(4)OH .

    Calculate the pH of 0.01 M solution of NH_(4)CN . Given that the dissociation constants are : K_(a) for HCN = 6.2xx10^(-10) and pK_(b) for NH_(3)=1.6xx10^(-5) .

    Calculate the pH of 0.1 M acetic acid solution if its dissociation constant is 1.8 xx 10^(-5). If 1 litre of this solution is mixed with 0.05 mole of HCI, what will be pH of the mixture?

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