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Give the mathematical expression for the...

Give the mathematical expression for the equlib rium constant `K_(c)` for the reaction.
`2SO_(3)(g)hArr2SO_(2)(g)+O_(2)(g)`

Text Solution

Verified by Experts

`K_(c)([SO_(2)]^(2)[O_(2)])/([SO_(3)]^(2))`
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Given the mathematical expression for the equilibrium constant K_c for the reaction. 2SO_3(g) hArr 2SO_2(g)+O_2(g)

At 700 K , the equilibrium constant K_(p) for the reaction 2SO_(3)(g)hArr2SO_(2)(g)+O_(2)(g) is 1.80xx10^(-3) kPa . What is the numerical value of K_(c ) in moles per litre for this reaction at the same temperature?

Knowledge Check

  • The equlibrium constnt (K_(rho)) for the reaction, 2SO_(2)(g)+O_(2)(g)hArr2SO_(3)(g) at 1000K is 3.5 atm^(-1) then find out equlibrium constnt (K_(rho)) for the reaction, 2SO_(3)(g)hArr2SO_(2)(g)+O_(2)(g)

    A
    `0.35` atm
    B
    `3.5`atm
    C
    `2.85` atm
    D
    `0.285` atm

  • What is the equilibrium expression K_c , for the reaction : 2S(s)+3O_(2)(g)hArr 3SO_3(g) ?

    A
    `K_c=(2[SO_3])/((2[S]+3[O_2]))`
    B
    `K_c=(2[SO_3])/(3[O_2])`
    C
    `K_c=(2[SO_3]^2)/([S]^2+[O_2]^3)`
    D
    `K_c=([SO_3]^2)/([O_2]^3)`

  • Given that the equilibrium constant for the reaction 2SO_(2)(g)+O_(2)(g)hArr2SO_(3)(g) has a value of 270 at a particular temperaturee. What is the vlaue of the equilibrium constant for the following reaction at same temperaturee SO_(3)(g)hArrSO_(2)(g)+1/2O_(2)(g)

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    `1.8xx10^(-3)`
    B
    `3.6xx10^(-3)`
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    `6.0xx10^(-2)`
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