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Three metals A, B and C are arranged in ...

Three metals A, B and C are arranged in increasing order of standard reduction electrode potential, hence their chemical reactivity order will be

A

`A lt B lt C`

B

`A gt B gt C`

C

`B gt C gt A`

D

`A=B=C`

Text Solution

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The correct Answer is:
To determine the chemical reactivity order of metals A, B, and C based on their standard reduction potentials (SRP), we can follow these steps: ### Step 1: Understand Standard Reduction Potential Standard reduction potential (SRP) is a measure of the tendency of a chemical species to gain electrons and be reduced. Metals with lower SRP values are more likely to lose electrons and act as reducing agents, while those with higher SRP values are more likely to gain electrons and act as oxidizing agents. ### Step 2: Arrange Metals by SRP According to the problem, the metals are arranged in increasing order of their standard reduction potentials: - A < B < C This means: - Metal A has the lowest SRP (most reactive) - Metal B has a medium SRP - Metal C has the highest SRP (least reactive) ### Step 3: Determine Reactivity Order Since metals with lower SRP are more reactive (they can easily lose electrons), we can conclude that: - Metal A is the most reactive. - Metal B is less reactive than A but more reactive than C. - Metal C is the least reactive. ### Step 4: Write the Reactivity Order From the above analysis, the order of reactivity from most reactive to least reactive is: - A > B > C ### Final Answer The chemical reactivity order of metals A, B, and C is: **A > B > C** ---
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Knowledge Check

  • K, Ca and Li metals may be arranged in the decreasing order of their standard electrode potential as

    A
    K, Ca, Li
    B
    Ca, K, Li
    C
    Li, Ca, K
    D
    Ca, Li, K
  • K,Ca and Li metals may be arranged in the decreasing order of their standard electrode potentials as

    A
    `K,Ca, Li`
    B
    `Li,K,Ca`
    C
    `Li, Ca,K`
    D
    `Ca,Li, K`
  • Which defines the standard reduction electrode potential of Zn^(2+) ions

    A
    `Zn^(2+) (aq) + 2 e^(-) to Zn(s) , [Zn^(2+)] = 1 M`
    B
    `Zn(g) to Zn^(2+) + 2e^(-) , [Zn^(2+)] = 1 M`
    C
    `Zn^(2+) (aq) to Zn(s) + 2e^(-) , [ Zn^(2+)] = 1 M`
    D
    `Zn^(2+) (g) + 2 e^(-) to Zn(s) - 2e^(-) , [Zn^(2+)] = 1 M`
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