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When a white powder (A) is strongly heat...

When a white powder (A) is strongly heated, it gives of a colourless, odourless gas (B) which turns lime water milky (C) and if the passage of this gas is continued the milkiness disappears and gives a solution (D). The solid residue (E) is yellow when hot, but turns white on cooling. Idnetify (A) to (E) with help of the equations.

Text Solution

Verified by Experts

The reaction can be explain if we consider the compound (A) to be `ZnCO_(3)`
`underset((A))(ZnCO_())rarrunderset((E))(ZnO)+underset((B))(CO_(2))`
`CaO+CO_(2)rarrunderset("(milky white)")(CaCO_(3))`
`CaCO_(3)+H_(2)O+underset("(excess)")(CO_(2))rarrunderset("(D)")underset("Soluble")(Ca(HCO_(3))_(2))`
`ZnO` is yellow when hot and white when cold.
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Knowledge Check

  • A white solid 'A' on heating gives off a gas which turns lime water milky. The residue is yellow when hot but turns white on cooling. This solid 'A' is

    A
    Zinc sulphide
    B
    Zinc carbonate
    C
    Lead sulphate
    D
    Lead carbonate

  • Which alkene on heating with hot and conc. KMnO_(4) solution gives acetone and a gas, which turns lime water milky -

    A
    2–Methyl–2–butene
    B
    Isobutylene
    C
    1–Butene
    D
    2–Butene

  • A gas 'X' turns lime water milky. The milkiness dissappears if excees of 'X' is passed. Milkiness appears on heating the colourless solution then 'X' is:

    A
    `NO_(2)`
    B
    `CO_(2) `
    C
    `H_(2)S`
    D
    `NH_(3)`