A : The oxidation number of S is +6 in `H_(2)SO_(4)`.
R : `H_(2)SO_(4)` has one peroxide linkage.

Options

A. If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1).
B. If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2).
C. If Assertion is true statement but Reason is false, then mark (3).
D. If both Assertion and Reason are false statements, then mark (4).

Answer

To analyze the statements given in the question, we need to evaluate both parts:

**Statement A**: The oxidation number of S is +6 in H₂SO₄.
**Statement R**: H₂SO₄ has one peroxide linkage.

### Step-by-Step Solution:

1. **Determine the oxidation state of sulfur in H₂SO₄**:
- The formula for sulfuric acid is H₂SO₄.
- In H₂SO₄, hydrogen (H) has an oxidation state of +1, and oxygen (O) has an oxidation state of -2.
- The total contribution from the two hydrogen atoms is:
\[ 2 \times (+1) = +2 \]
- The total contribution from the four oxygen atoms is:
\[ 4 \times (-2) = -8 \]
- Let the oxidation state of sulfur (S) be \( x \). The overall charge of the molecule is neutral (0), so we can set up the equation:
\[ +2 + x - 8 = 0 \]
- Simplifying this gives:
\[ x - 6 = 0 \implies x = +6 \]
- Therefore, the oxidation number of sulfur in H₂SO₄ is indeed +6. **Statement A is true.**

2. **Evaluate the presence of peroxide linkage in H₂SO₄**:
- A peroxide linkage is characterized by the presence of an O-O bond, where oxygen is in the -1 oxidation state.
- In H₂SO₄, the structure does not contain any O-O bonds. Instead, all oxygen atoms are bonded to sulfur and are in the -2 oxidation state.
- Therefore, H₂SO₄ does not have any peroxide linkages. **Statement R is false.**

3. **Conclusion**:
- Statement A is true, while Statement R is false.

### Final Answer:
- A is true: The oxidation number of S is +6 in H₂SO₄.
- R is false: H₂SO₄ does not have one peroxide linkage.