Vapour pressure of water is 360 mm Hg. How much urea should be added to 200 mL water to reduce its vapour pressure by 0.05%?Molecular wt. of urea=60

Explanation

To solve the problem of how much urea should be added to 200 mL of water to reduce its vapor pressure by 0.05%, we can follow these steps:

### Step 1: Calculate the reduction in vapor pressure
The initial vapor pressure of water (P₀) is given as 360 mm Hg. To find the reduction in vapor pressure (ΔP), we can calculate 0.05% of P₀.

\[ \Delta P = \frac{0.05}{100} \times P₀ = \frac{0.05}{100} \times 360 = 0.18 \text{ mm Hg} \]
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